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Let vecu,vecv,vecw be such that |vecu|=1...

Let `vecu,vecv,vecw` be such that `|vecu|=1,|vecv|=2,|vecw|3`. If the projection of `vecv along vecu` is equal to that of `vecw along vecv,vecw` are perpendicular to each other then `|vecu-vecv+vecw|` equals (A) 2 (B) `sqrt(7)` (C) `sqrt(14)` (D) `14`

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