A wire of length L extends by `l` on application of force F. Suppose the wire is cut into 3 equal parts and the same force is applied to one of them. Now the extension will be

A wire extends by 'l' on the application of load 'mg' . Then the energy stored in it is

Length and force constant of a spring are L and K respectively. When a force T is applied on it an elongation x is produced. Now the spring is cut into two equal parts and they are connected parallel with each other and the same force T is applied on it. What will be the elongation now?

In which case there is maximum extension in the wire, if same force is applied on each wire

A composite wire is prepared by joining a tungsten wire and steel wire Both the wires are of the same length and same area of cross section. If this composite wire is suspended to a rigid support and a force is applied to its free end, it gets extended by 3.25 mm. Calculate the increase in length of tungsten wire and steel wire separately.

A wire has an elongation of 0.04m when a force F is applied on it . Now its length & diameter are double and same force F is applied on it. Find new elongation in the wire

Two wires of same diameter of the same material having the length l and 2l .If the force F is applied on each, the ratio of the work done in the two wires will be

A force F is applied on the wire of radius r and length L and change in the length of wire is l . If the same force F is applied on the wire of the same material and radius 2r and length 2L. Then the change in length of the other wire is

Two wires of same diameter of the same material having the length l and 2l If the force F is applied on each, the ratio of the work done in two wires will be

Two wires of same diameter of the same material having the length l and 2l If the force F is applied on each, the ratio of the work done in two wires will be