The sum of first `n` odd natural numbers is `2n-1` (b) `2n+1` (c) `n^2` (d) `n^2-1`

Property 6 The sum of first n odd natural numbers is n^(2)

The mean of first n odd natural number is (a) (n+1)/2 (b) n/2 (c) n (d) n^2

The mean of first n odd natural numbers is (n^2)/(81) , then n= (a) 9 (b) 81 (c) 27 (d) 18

If the sum of first n even natural numbers is equal to k xx the sum of first n odd natural number then k=(1)/(n) b.(n-1)/(n) c.(n+1)/(2n)d .(n+1)/(n)

For natural number n , 2^n (n-1)!lt n^n , if

The sum of squares of first n natural numbers is given by 1/6 n (n+1)(2n+1) or 1/6 (2n^3 + 3n^2 + n) . Find the sum of squares of the first 10 natural numbers.

Statement 1: The variance of first n even natural numbers is (n^2-1)/4 Statement 2: The sum of first n natural numbers is (n(n+1)/2 and the sum of squares of first n natural numbers is (n(n+1)(2n+1)/6 (1) Statement1 is true, Statement2 is true, Statement2 is a correct explanation for statement1 (2) Statement1 is true, Statement2 is true; Statement2 is not a correct explanation for statement1. (3) Statement1 is true, statement2 is false. (4) Statement1 is false, Statement2 is true

The sum of first n natural numbers is given 1/2 n^2 +1/2n . Find (i) The sum of first 5 natural numbers. (ii) The sum of first 11 natural numbers. (iii) The sum of natural numbers from 11 to 30.

If S_(n) denotes the sum of first 'n' natural numbers then s_(1)+S_(2)x+S_(3)x^(2)+.........+S_(n) x^(n-1)+......oo=(1-x)^(-n) then n is