" (viii) "(1+sqrt(2))/(2-sqrt(2))quad [2014]quad " (ix) "(3)/(3)

(1+2sqrt(3))/(2-sqrt(3))

Rationalise the denominator of each of the following. (i) (1)/(sqrt(7)) (ii) (sqrt(5))/(2sqrt(3)) (iii) (1)/(2+ sqrt(3)) (1)/(sqrt(3)) (v) (1)/((5+3sqrt(2)) (vi) (1)/(sqrt(7) - sqrt(6)) (vi) (1)/(sqrt(7) - sqrt(6)) (viii) (1+ sqrt(2))/(2-sqrt(2)) (ix) (3-2sqrt(2))/(3+2sqrt(2))

(sqrt(3)+1+sqrt(3)+1)/(2sqrt(2))

Rationales the denominator and simplify: (sqrt(3)-sqrt(2))/(sqrt(3)+sqrt(2)) (ii) (5+2sqrt(3))/(7+4sqrt(3)) (iii) (1+sqrt(2))/(3-2sqrt(2)) (2sqrt(6)-sqrt(5))/(3sqrt(5)-2sqrt(6)) (v) (4sqrt(3)+5sqrt(2))/(sqrt(48)+sqrt(18)) (vi) (2sqrt(3)-sqrt(5))/(2sqrt(3)+3sqrt(3))

(-sqrt(3)/2 + sqrt(3))/(1/sqrt(2)-1)=

Simplify (i) (4+ sqrt(5))/(4-sqrt(5))+(4-sqrt(5))/(4+sqrt(5)) (ii) (1)/(sqrt(3) + sqrt(2)) - (2)/(sqrt(5)-sqrt(3)) -(2)/(sqrt(2) - sqrt(5)) (iii) (2+sqrt(3))/(2-sqrt(3)) + (2-sqrt(3))/(2+sqrt(3)) + (sqrt(3)-1)/(sqrt(3)+1) (iv) (2+sqrt(6))/(sqrt(2)+sqrt(3))+(6sqrt(2))/(sqrt(6)+sqrt(3)) -(8sqrt(3))/(sqrt(6)+sqrt(2))

Rationalise the denominator of the following (i) 2/(3sqrt3) , (ii) sqrt40/sqrt3 ,(iii) (3+sqrt2)/(4sqrt2) (iv) 16/(sqrt41-5) ,(v) (2+sqrt3)/(2-sqrt3) , (vi) sqrt6/(sqrt2+sqrt3) (vii) (sqrt3+sqrt2)/(sqrt3-sqrt2) ,(viii) (3sqrt5+sqrt3)/(sqrt5-sqrt3) , (ix) (4sqrt3+5sqrt2)/(sqrt48+sqrt18)

The value of (2 + sqrt(3))/(2- sqrt(3)) + (2- sqrt(3))/(2 + sqrt(3)) + ( sqrt(3) + 1)/(sqrt(3) -1) is

(sqrt(2)(2+sqrt(3)))/(sqrt(3)(sqrt(3)+1))xx(sqrt(2)(2-sqrt(3)))/(sqrt(3)(sqrt(3)-1)) is equal to 3sqrt(2)(b)(sqrt(2))/(3) (c) (2)/(3) (d) (1)/(3)