Construct a triangle similar to a given ` A B C` such that each of its sides is `(5//7)^(t h)` of the corresponding sides of ` A B C` . It is given that `A B=5c m` , `B C=7c m` and `/_A B C=50o`

To constuct a triangle similar to a given DeltaABC with its sides (7)/(3) of the corresponding side of DeltaABC , draw a ray BX making acute angle with BC and X lies on the opposite side of A with respect of BC. The points B_(1),B_(2),…..,B_(7) are located at equal distances on BX, B_(3) is joined to C and then a line segment B_(6)C' is drawn parallel to B_(3)C , where C' lines on BC produced. Finally line segment A'C' is drawn parallel to AC.

Draw Delta ABC with sides = 6 cm, 8 cm and 9 cm and then construct a triangle similar to Delta A'B'C whose sides are (3)/(5) or the corresponding sides of Delta ABC .

If sides of triangle ABC are a, b, and c such that 2b = a + c , then

Draw a triangle ABC with BC=7cm, /_B=45^0a n d/_C=60^0dot Then construct another triangle, whose sides are 3/5 times the corresponding sides of triangle A B Cdot

The area of a triangle is half the product of any of its sides and the corresponding altitude. GIVEN : A A B C in which A L is the altitude to the side B Cdot TO PROVE : a r( A B C)=1/2(B CxA L) CONSTRUCTION : Through C and A draw C D B A and A D B C respectively, intersecting each other at Ddot

P and Q are points on sides A B and A C respectively of A B C . If A P=3c m , P B=6c m , A Q=5c m and Q C=10 c m , show that B C=3\ P Q .

If the altitude from one vertex of a triangle bisects the opposite side, then the triangle is isosceles. GIVEN : A A B C such that the altitude A D from A on the opposite side B C bisects B C i.e., B D=D Cdot TO PROVE : A B=A C i.e. the triangle A B C is isosceles.

In A B C ,\ \ /_A=60o . Prove that B C^2=A B^2+A C^2-A B.A C .