At a point on level ground, the angle of elevation of a vertical tower is found to be such that its tangent is `5//12` . On walking 192 metres towards the tower, the tangent of the angle of elevation is `3//4` . Find the height of the tower.

At a point, the angle of elevation of a tower is such that its tangent is 5/12 . On walking 240 m nearer to the tower, the tangent of the angle of elevation becomes 3/4 . Find the height of the tower.

From a point on a cricket ground,the angle of elevation of the top a lower is found to 30^(@) at a distance of 225m from the tower.On walking 150m towards the tower,again the angle of elevation is found Find the new angle of elevation and the height of the tower

The angle of elevation theta of the top of vertical tower from a point on the ground is tantheta where tantheta=5/12 . One walking 192 meters towards the tower in the same straight line, the elevation is alpha where tanalpha=3/4 . Find the height of the tower.

The angle of elevation of the top of a tower at a point A on the ground is 30^(@) . On walking 20 meters toward the tower, the angle of elevation is 60^(@) . Find the height of the tower and its distance from A.

The angle of elevation of the top of a tower at a point on the ground is 30o.On walking 24m towards the tower,the angle of elevation becomes 60_(0). Find the height of the tower.