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Fig. 15.17, shows a sector of a circle, ...

Fig. 15.17, shows a sector of a circle, centre `O` , containing an angle `thetao` , prove that: (FIGURE) (i) Perimeter of the shaded region is `r\ (tantheta+sectheta+(pitheta)/(180)-1)` (ii) Area of the shaded region is `(r^2)/2\ (tantheta-(pitheta)/(180))`

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Figure shows a sector of a circle,centre O, containing an angle theta. Prove that ( i) Perimeter of the shaded region is r(tan theta+sec theta+(pi theta)/(180)-1)( ii) Area of shaded region is (r^(2))/(2)(tan theta-pi(theta)/(180))

In the given figure,is shown a sector OAP of a circle with centre 0, containing /_ theta. AB is perpendicular to the radius OA and meets OP produced at B.Prove that the perimeter of shaded region is r[tan theta+sec theta+pi(theta)/(180)-1]

Figure shows a sector of a circle of radius r containing an angle theta^(@) The area of the sector is Acm^(2) and the perimeter is 50cm. Prove that theta=(360)/(pi)((25)/(r)-1) and A=25r-r^(2)

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If Figure - 4, AB and CD are two diameter of a circle (with centre O) perpendicular to each other and OD is the diameter of the smaller circle. IF OA = 7 cm, then find the area of the shaded region.

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RD SHARMA-AREAS RELATED TO CIRCLES-All Questions
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