The ratio of the areas of a circle and an equilateral triangle whose diameter and a side are respectively equal, is (a) `pi\ :sqrt(2)` (b) `pi\ :sqrt(3)` (c) `sqrt(3)\ :pi` (d) `sqrt(2)\ :pi`

The ratio of the area of a square of side a and that of an equilateral triangle of side a, is 2:1 (b) 2:sqrt(3)4:3( d) 4:sqrt(3)

If area of a circle inscribed in an equilateral triangle is 48pi square units, then perimeter of the triangle is (a) 17sqrt(3) units (b) 36 units (c) 72 units (d) 48sqrt(3) units

The area of a circle inscribed in an equilateral triangle is 154cm^(2). Find the perimeter of the triangle.[Use pi=22/7and sqrt(3)=1.73]

If the area of a square is same as the area of the circle, then the ratio of their perimeters, in terms of pi , is (a) pi\ :sqrt(3) (b) 2\ :sqrt(pi) (c) 3\ :pi (d) pi\ :sqrt(2)

In Fig. 15.111, if A B C is an equilateral triangle, then shaded area is equal to (FIGURE) (a) (pi/3-(sqrt(3))/4)r^2 (b) (pi/3-(sqrt(3))/2)r^2 (c) (pi/3+(sqrt(3))/4)r^2 (d) (pi/3+sqrt(3))r^2

If the circumference and the area of a circle are numerically equal, then diameter of the circle is (a) pi/2 (b) 2pi (c) 2 (d) 4

The area of a square is equal to the area of a circle.The ratio between the side of the square and the radius of the circle is (a) sqrt(pi):1 (b) 1:sqrt(pi)(c)1:pi(d)pi:1

If the areas of a circle and a square are equal then the ratio of their perimeters is (a)1:1 (b) 2backslash pi(c)pi backslash2(d)sqrt(pi)backslash2

A sphere and a cone are of same radii and height,if the volume of sphere is (88)/(21)cm^(3) then the curved surface area of cone is (A) pi sqrt(2) (B) pi sqrt(5) (C) pi sqrt(7) (D) pi sqrt(11)

A pair of tangents is drawn to a unit circle with center at the origin and these tangents intersect at A enclosing an angle of 60^0 . The area enclosed by these tangents and the arc of the circle is 2/(sqrt(3))-pi/6 (b) sqrt(3)-pi/3 pi/3-(sqrt(3))/6 (d) sqrt(3)(1-pi/6)