A solid is in the form of a cylinder with hemispherical ends. Total height of the solid is 19 cm and the diameter of the cylinder is 7 cm. Find the volume and total surface area of the solid.

A solid is in the form of a cylinder with hemispherical ends. The total height of the solid is 19 cm and the diameter of the cylinder is 7 cm. Find the volume and total surface area of the solid (Use pi=22//7 )

A solid is in the form of a cylinder with hemispherical ends. The total height of the solid is 20 cm and the diameter of the cylinder is 7 cm. Find the total volume of the solid. (Use F = 22/7 )

A solid is in the form of a right circular cylinder with hemispherical ends.The total length of the solid is 35cm. The diameter of the cylinder is (1)/(4) of its height.The surface area of the solid is (a) 462cm2 (b) 693cm2 (c) 750cm2(d)770cm2

Combination of cylinder and hemisphere: A solid is in the form of a cylinder with hemispherical ends.The the whole length of the solid is 108cm and the diameter of the hemispherical ends is 36cm; Find the cost of polishing the surface of the solids at the rate of 7 paise per sq.cm.

The solid is composed of a cylinder with hemispherical ends.If the whole length of the solid is 108cm and the diameter of the hemispherical ends is 36cm ,find the cost of polishing the surface of the solid at the rate of 7 paise per sq.cm(U sin=(22)/(7))

The diameter of a cylinder is 28 cm and its height is 20 cm . The total surface area of the cylinder is

A solid is composed of a cylinder with hemispherical ends.If the whole length of the solid is 104 cm and the readius of each of its hemispherical ends is 7 cm , find the cost of polishing its surface at the rate of ₹ 10 per dm^2

The radius and height of a cylinder are in the ratio 7:2. If the volume of the cylinder is 8316 cm^(3) ,find the total surface area of the cylinder.

The radius and height of a cylinder are in the ratio 7:2 . If the volume of the cylinder is 8316cm^(3) , find the total surface ara of the cylinder.