If the radius of the base of a right circular cylinder is halved, keeping the height same, what is the ratio of the volume of the reduce cylinder to that of the original.

Explanation

`V_{2} =pi(frac{r}{2})^{2} h=frac{pi r^{2} h}{4} `

` V_{1} =pi r^{2} h=pi r^{2} h `


`frac{V_{2}}{V_{1}} =(frac{pi r^{2} h}{4} )/(pi r^{2} h)= (pi r^{2} h)/4
times 1/(pi r^{2} h)`

`=frac{1}{4}= 1: 4 `