Find  `lim_(n->oo)[4n^2+6n+2]/4n^2`

If f(x) = lim_(n->oo) tan^(-1) (4n^2(1-cos(x/n))) and g(x) = lim_(n->oo) n^2/2 ln cos(2x/n) then lim_(x->0) (e^(-2g(x)) -e^(f(x)))/(x^6) equals

Find lim_ (n rarr oo) [(n ^ (4) +1) ^ ((1) / (2)) - (n ^ (4) -1) ^ ((1) / (2))] -: n ^ (- 2)

Find lim_(n rarr oo)(2n-1)(2n)n^(2)(2n+1)^(-2)(2n+2)^(-2)

Find lim_ (n rarr oo) [(n ^ (3) +1) ^ ((1) / (2)) - n ^ ((3) / (2))] -: n ^ ((3) / ( 2))

S1: lim_(n->oo) (2^n + (-2)^n)/2^n does not exist S2: lim_(n->oo) (3^n + (-3)^n)/4^n does not exist

Find Lim {x->oo}{ (1+1/(n^2))^(2/n^2)(1+4/(n^2))^(4/n^2).....(1+(n^2)/(n^2))^(2n/n^2)}

Find lim_ (n rarr oo) 2 ^ (n-1) (10 + n) (9 + n) ^ (- 1) 2 ^ (- n)

lim_(n->oo)(n(2n+1)^2)/((n+2)(n^2+3n-1)) is equal to (a)0 (b) 2 (c) 4 (d) oo

lim_(n->oo)(n(2n+1)^2)/((n+2)(n^2+3n-1)) is equal to (a)0 (b) 2 (c) 4 (d) oo

lim_(n->oo)(n(2n+1)^2)/((n+2)(n^2+3n-1)) is equal to (a)0 (b) 2 (c) 4 (d) oo