If `x=1` , y=2 is a solution of the equation `a^2x+a y=3,` then find the values of `a`

Explanation

Here given x=1 and y=2 is a solution of equation `a^2x+ay=3`.
Now put the value of x and y in the given equation.So, we get :
`a^2times1+atimes2=3`
`a^2+2a=3`
`a^2+2a-3=0`
By splitting the middle term
`a^2+(3-1)a-3=0`
`a^2+3a-a-3=0`
`a(a+3)-1(a+3)=0`
`(a-1)(a+3)=0`
So, value of a=1 and a=-3