If `x=k^2` and `y=k` is a solution of the equation `x-5y+6=0` then find the values of `k`

Explanation

Here put the value of `x=k^2` and `y=k` in the equation `x-5y+6=0`.
Now ,
`k^2-5k+6=0`
By splitting the middle term
`k^2-2k-3k+6=0`
`k(k-2)-3(k-2)=0`
`(k-2)(k-3)=0`
Hence, the value of k are 2 and 3.