If `x=1\ a n d\ y=6` is a solution of the equation `8x-a y+a^2=0` , find the value of `a`

Explanation

Here, Given equation is `8x-ay+a^2=0`
Now put the value of `x=1 and y=6` in the given equation
`8(1)-a(6)+a^2=0`
`8-6a+a^2=0`
It can be re-arranged as :
`a^2-6a+8=0`By splitting the middle term
`a^2-4a-2a+8=0`
`a(a-4)-2(a-4)=0`
`(a-2)(a-4)=0`
Hence, the values of a are 2 and 4.