Draw the graph of each of the following linear equations in two variables: `3x+5y=15` (ii) `x/2-y/3=2`

Explanation

Solution
(i)'3x+5y = 15
3x = 15-5y
X = (15-5y)/3'
Putting 'y = 0' we get 'x = (15-5 x 0)/3 = 5'
Putting 'y = 3' we get x = (15-5 x 3)/3 = 0'
Thus, we get the following table giving the two points on the linerepresented by the equation '3x+5y-15'
(ii) '2/x− 3/y =2'
To draw the graph, we need at least two solutions to the equation
Put 'x=0
2/0− 3/y=2
⇒− 3/y =2
⇒y=−6'
So '(0,−6)' is a solution of the equation
Put 'y=0'
2/x − 3/0 =2
⇒ 2/x =2
⇒x=4'
So '(4,0)' is a solution of the equationWith these two solutions we can draw linear graph of '2/x − 3/y=2'.