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In a quadrilateral `A B C D ,A O` and `B O` are the bisectors of `/_A` and `/_B` respectively. Prove that `/_A O B=1/2(/_C+/_D)dot`

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"In a quadrilateral `A B C D ,A O` and`B O` are the bisectors of `/_A` and `/_B` respectively
from angle sum `A+B+C+D=360^@`
`2(/_1+/_2)+C+D=360^@`
`2(360^@-/_AOB)+C+D=360^@`
we get `/_A O B=1/2(/_C+/_D)`"
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