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The diagonals of a parallelogram ABCD in...

The diagonals of a parallelogram `ABCD` intersect at `OA` line through `O` intersects `AB` at `X and DC` at `Y` Prove that `OX=OY`

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Verified by Experts

"Consider `/_\AXO` and `/_\CYO`
`AO=CO` [Diagonals bisect each other]
`/_AOX=/_COY` [Vertically opposite angles]
`/_AXO=/_CYO` [Alternate angles]
so`/_\AXO~=/_\CYO` [AAS congruency]
so `OX=OY` (from CPCT)"
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