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A B C D is a parallelogram. L\ a n d\ M ...

`A B C D` is a parallelogram. `L\ a n d\ M` are points on `A B\ a n d\ D C` respectively and `A L=C M` . Prove that `L M\ a n d\ B D` bisect each other.

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Here `AB=CD`(opposite sides of parallelogram)
Subtraction AL from both sides `AB−AL=CD−AL`
`AB−AL=CD−CM` (because `AL=CM`)
`LB=DM`
In triangle BLO and MDO `/_MDO=/_LBO` (because `AB∣∣CD` and taking DB as transversal)
...
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