Find the measure of all the angles of a parallelogram, if one angle is `24^@` less than twice the smallest angle.

Explanation

let the smallest angle of a parallelogram be `x^@`
then according to the question its adjacent angle will be `(2x-24)^@`
we know that the sum of the adjacent angles is `180^@`
so,
`x^@+(2x-24)^@=180^@`
`x=68^@` and its adjacent angle is `112^@`
so the angles are `68^@,68^@,112^@,112^@`