int_(0)^(2 pi)|1+2cos x|dx

int_(0)^(2 pi)|cos x|dx

int_(0)^( pi)|cos x|dx=2

Prove that, int_(0)^(pi)log(1+cos x)dx=-pi log2 , given int_(0)^((pi)/(2))log((sin x))dx=(pi)/(2)"log"(1)/(2) .

If A=int_(0)^( pi)(cos x)/((x+2)^(2))dx, then int_(0)^( pi/2)(sin2x)/(x+1)dx is equal to

If I_(1)=int_(0)^(pi//2)"x.sin x dx" and I_(2)=int_(0)^(pi//2)"x.cos x dx" , then

If A=int_((rho)/(2))^((pi)/(2))cos(sin x)dxB=int_(0)^((pi)/(2))sin(cos x)dx and C=int_(0)^((pi)/(2))cos(x)dx

Evaluate int_(0)^(pi)(1)/(3+2cos x) dx

If int_(0)^( pi)(1)/(a+b cos x)dx=(pi)/(sqrt(a^(2)-b^(2))), then int_(0)^( pi)(1)/((a+b cos x)^(2))dx is

If P=int_(0)^(3pi)f(cos^(2)x) dx and Q=int_(0)^(pi) f(cos^(2)x)dx , then -

If P = int_(0)^(3pi) f(cos^(2)x)dx and Q=int_(0)^(pi) f(cos^(2)x)dx , then