In a A B C ,\ B M\ a n d\ C N are perpe...

In a ` A B C ,\ B M\ a n d\ C N` are perpendiculars from `B\ a n d\ C` respectively on any line passing through `Adot` If `L` is the mid-point of `B C` , prove that `M L=N L` .

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here in triangles `/_\BLM` and `/_\CLN`
`/_BML=/_CNL=90^0`
`BL=LC` (L is a mid point BC).
`/_MLB=/_NLC` ( vertically opposite angles) Therefore,
`/_\BLM~=/_\CLN`
Hence,from CPCT we have `LM=LN`

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