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In Figure, triangle A B C is right-angle...

In Figure, triangle `A B C` is right-angled at `Bdot` Give that `A B=9C M ,\ A C=15 C M , and D , E` are the mid-points of the sides `AB and AC` respectively, calculate
The length of `BC`
(ii) The area of ` A D E`

Text Solution

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in traingle ABC,
`/_B=90^0`
so from pythagorus theorem, `BC^2=AC^2-AB^2`
`=15^2-9^2`
`BC=12cm`
here D ,E are mid points of AB and AC
so`DE||BC`
so `/_ADE=/_B=90^0`
since DE is line joining mid points of AB ,AC so
`DE=(BC)/2=6cm`
so area of
`/_\ADE=(1/2)xx9xx6=27cm^2`
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