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`A B C` is a triangle and through `A ,\ B ,\ C` lines are drawn parallel to `B C ,\ C A\ a n d\ A B` respectively intersecting at `P ,\ Q\ a n d\ R` . Prove that the perimeter of ` P Q R` is double the perimeter of ` A B C`

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as we know , line joining mid point of two sides is parallel to third side and
is half of the third side
so here,`PQ||BC`,`QR||AB`and `RP||AC`
`PQ=2xxBC`
`QR=2xxAB`
`PR=2xxAC`
so perimetre of `PQR=PQ+QR+RP`
perimetre of `PQR=2BC+2AB+2AC`
perimetre of `PQR=2(BC+AB+AC)`
...
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