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A B C is a triangle. D is a point on A B...

`A B C` is a triangle. `D` is a point on `A B` such that `D=1/4A B\ a n d\ E` is a point on `A C` such that `A E=1/4A Cdot` Prove that `D E=1/4B C`

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Verified by Experts

A is a common angle in `/_\ABC `and `/_\ADE`
here `(AD)/(AB)=(AE)/(AC)=1/4`
therefore ,`/_\ABC ~ /_\ ADE` ( SAS)
`(DE)/(BC)=(AD)/(AB)=(AE)/(AC)=1/4`
so `DE=(1/4)BC`
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