Find the measure of all the angles of a parallelogram, if one angle is `24^@` less than twice the smallest angle.

Explanation

Given: First angle of a parallelogram is `24^@` less than twice the smallest angle.

Solution : Let the smallest angle be x.

A.T.Q

`x+2x-24^@=180^@`

`3x=180^@+24^@`

`3x=204^@`

`x=68^@`

Second angle = `2x-24^@`=`2(68^@)-24^@`

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