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In a parallelogram A B C D , if /D A B=7...

In a parallelogram `A B C D` , if `/_D A B=75^@` and` /_D B C=60^@,` then `/_B D C=` `75^@` (b) `60^@` (c) `45^@` (d) `55^@`

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Given : ABCD is a parallelogram
`angleDAB=75^@` and `angleDBC=60^@`
solution: As we know that opposite angles of a parallelogram are equal
`angleDAB=angleBCD`
`therefore` `angleBDC+angleDBC+angleBCD=180^@`
`angleBDC=180^@-75^@-60^@`
`angleBDC=45^@`
Hence, option (c) is correct.
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