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In a rhombus A B C D , if /A C B=40^@, t...

In a rhombus `A B C D ,` if `/_A C B=40^@,` then `/_A D B=`(a) `70^@` (b) `45^@` (c) `50^@` (d) `60^@`

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Given: ABCD is a rhombus, `angleACB=40^@`
Solution : `therefore` `angleBCD=2xxangleACB`
`2xx40^@=80^@`
But `angleBCD+angleADC=180^@`(sum of consecutive angles of a parallelogram)
`80^@+angleADC=180^@`
`angleADC=100^@`
`therefore` `angleADB=1/2angleADC`
`1/2xx100^@`
...
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