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In A B C ,\ E is the mid-point of me...

In ` A B C ,\ E` is the mid-point of median `A D` such that `B E` produced meets `A C\ ` at `Fdot` If `A C=10. 5\ C M ,` then `A F=` 3cm (b) 3.5cm (c) 2.5cm (d) 5cm

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Given : In `triangleABC`, E is the mid -point of median AD such that BE produced meets AC at F. Also, AC = 10.5 cm.
Cons. : Draw `DG|\| AF`
In `triangleADG`, E is mid -point of `AD` and `EF|\| DG`
`therefore` `F` is mid -point of `AG`
`AF=FG`____1
In `triangleBCF`, `D` is mid -point of `BC` and `DG|\| BF`
`therefore` `G` is mid -point of `FC`
`FG=GC`
...
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