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A D is one of the medians of a A B Cd...

`A D` is one of the medians of a ` A B Cdot. X` is any point on `AD` . Show that `ar( ABX)=ar ( A C X)`

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Solution:
`/_\ ABC`,
`AD` is median,
`ar(/_\ABD)=ar(/_\ADC)......(1)`
`/_\XBC,`
`XD` is median,
`ar(XBD) = ar(XDC)......(2)`
Substract eq `(2)` from `(1)`
`ar(/_\ABD) -ar(/_\XBD) = ar(/_\ADC) - ar(/_\ XDC)`
`ar(/_\ABX)=ar(/_\ACX)`
Hence proved.
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