Show that the area of a rhombus is half the product of the lengths of its diagonals. Given: A rhombus `A B C D` whose diagonals `AC and BD` intersect at `Odot` To Prove:ar (rhombus`A B C D)=1/2(A C * B D)`

Explanation

Solution:
`ar(ABCD)=ar(/_\ ABC)+ar(/_\ADC)`
`=1/2 xx AC xx BD + 1/2 xx AC xx DO`
`1/2 (AC)[AD +BD]`
`area\ (r hom b u s\ABCD) =1/2 xx AC xx BD`
Hence proved.