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D is the mid-point of side B C of \ A...

`D` is the mid-point of side `B C` of `\ A B C\ a n d\ E` is the mid-point of `B Ddot` If `O` is the mid-point of `A E ,` prove that `a r\ (\ B O E)=1/8a r\ (\ A B C)`

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Given: D is the midpoint of side BC of ∆ABC. E is the midpoint of BD and O is the midpoint of AE.
Since AD and AE are the medians of `triangleABC` and `triangleABD` respectively.
`therefore` ar(`triangleABD`)=`1/2`ar(`triangleABC)`_____1
ar(`triangleABE`)=`1/2`ar(`triangleABD`)____2
OB is a median of `triangleABE`
`therefore` ar(`triangleBOE`)=`1/2`ar(`triangleABE`)____3
From 1,2 and 3
ar(`triangleBOE`)=`1/8`ar(`triangleABC`) hence proved
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