`P Q R S` is a rectangle inscribed in a quadrant of a circle of radius `13 c mdot` `A` is any point on `P Qdot` If `PS=5cm , ` then find `a r ( R A S)`

Explanation

Solution: As, PQRS is a rectangle with PS=5cm and PR=13cm

In `trianglePSR`

`SR^2=PR^2-PS^2`

`SR^2`=`13^2-5^2`=`169-25`=`114`

SR=12

Now, area of `triangleRAS=1/2xxSRxxPS`

`1/2xx12xx5`

30

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