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`P` is any point on base `B C` of ` A B C\ a n d\ D` is the mid-point of `B CdotD E` is drawn parallel to `P A` to meet `A C` at `Edot` If `a r ( A B C)=12 c m^2` , then find area of ` E Q C`

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ABC is a triangle and D is the midpoint of BC and P is a point on BC such that DE∣∣PA.
`therefore` area(`triangleEQC`)=`1/2`area(`triangleABC`)
=`1/2xx12`=`6cm^2`(Given: area of `triangleABC=12cm^2`)
Hence, area of `triangleEQC=6cm^2`.
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