The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals `16 c m\ a n d\ 12 c m\ ` is `28\ c m^2` (b) `48\ c m^2` (c) `96\ c m^2` (d) `24\ c m^2`

Explanation

In rhombus ABCD,
P,Q,R and S are the mid points of sides AB, BC, CD and DA respectively.

Now, joined in order to get a quadrilateral PQRS.

Diagonals `AC = 16 cm` and `BD = 12 cm`

Area of `PQRS`=`1/2` area rhombus `ABCD`

`1/2xx(ACxxBD)/2`

`1/4xx16xx12 cm^2`

`48 cm^2`

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