The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides `8c m\ a n d\ 6\ c m` is a rhombus of area `24\ c m^2` (b) a rectangle of area `24 c m^2` a square of area `26\ c m^2` (d) a trapezium of area `14\ c m^2`

Explanation

Here, length of the rectangle = `8cm` and breadth of the rectangle = `6cm`

By joining the midpoints of the adjacent sides of a rectangle, we get a rhombus.
Let E, F, G and H be the mid-points of the sides of rectangle ABCD. Then, EFGH is a rhombus. Then, diagonals of rhombus EFGH are EG and HF. Here,` EG = BC = 8 cm` and `HF = AB = 6 cm`.

`therefore` area of rhombus=(product of diagonals`/2`)

`8xx(6/2)`

`24 cm^2`

Hence, joining the midpoints of the adjacent sides of the rectangle, we obtain a rhombus of area is `24cm^2`.


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