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The sum of length, breadth and depth of a cuboid is `19cm` and length of its diagonal is `11 cmdot` Find the surface area of the cuboid.

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given ,
`l+b+h=19cm`.......(1 )
`(l^2+b^2+h^2)^(1/2)=11cm`
`(l^2+b^2+h^2)=11^2cm^2`...(2)
it can be rewritten as,
`(l+b+h)^2-2(lb+bh+hl)=121`
`19^2-2(lb+bh+hl)=121`
`2(lb+bh+hl)=240cm^2`
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