I=int_(-1)^( pi)[cot x]dx

If I=int_(-2pi)^(5pi) cot^-1(tanx)dx . Then, 2I/pi^2 is ….

if int_(0)^( pi/2)(cot x)/(cot x+cos ecx)dx=m(pi-n) then the value of mn is

If int_(0)^(pi//2) (cot x)/(cot x+cosecx)dx=m(pi+n) , then m*n is equal to :

int_(pi//4)^(pi//2)cot x dx=

Evaluate: \int_(pi/4)^(pi/2) cot^2 x dx

If I_(1)=int_(0)^(pi//2)"x.sin x dx" and I_(2)=int_(0)^(pi//2)"x.cos x dx" , then

int_(0)^( pi/2)log[tan x*cot x]dx

int_(0)^(pi//4) cot x. " cosec"^(2) x dx

Statement-1: int_(0)^(pi//2) x cot x dx=(pi)/(2)log2 Statement-2: int_(0)^(pi//2) log sin x dx=-(pi)/(2)log2