A rectangular tank is `225 m ` by `162 m` at the base. With what speed must water flow into it through and aperture `60 cm` by `45 c m` that the level may be raised `20 c m` in `5 hou r s ?`

Explanation

Answer
The tank is in the shape of a cuboid.
Volume of a cuboid `=l xx b xx h.`
Since, after `5 `hours, the height of the water is `20cm`,

Volume of water in the tank in `5 hours =225 xx 162 xx 20/100m^3 =7290m^3`
Let x m/ hour be the speed of the water flowing thought the aperture.

Then, Volume of water flown through the aperture in `5 `hours `=(60/100 xx 45/100
xx5xxx)m^3`
Now, `27/20 x=7290=
7290xx20/27=5400` m/hr.Hence the required answer is `5400(m)/(hr)`.