If `V` is the volume of a cuboid of dimensions `a ,\ b ,\ c\ a n d\ S` is its surface area, then prove that `1/V=2/S(1/a+1/b+1/c)`

Explanation

Volume of a cuboid =`lxxbxxh`

Surface area of cuboid=`2(lbxxbhxxhl)`

`therefore` `2/s(1/l+1/b+1/h)`=`2s(bh+lh+lb)/lbh`

`2/s(1/a+1/b+1/c)=2/s(s/2v)`

On calculation

`2/s(1/a+1/b+1/c)=1/v`

`1/v=2/s(1/a+1/b+1/c)` Hence Proved.