Water in a canal 30 dm wide and 12 dm deep, is flowing with a velocity of 100 km per hour. How much area will it irrigate in 30 minutes if 8cm of standing water is desired?

Explanation

Here, width of canal(b) = 30dm and height(h)=12dm

So, `b=30/10`=`3m`

`h=12/10`=`1.2m`

Speed of water=`100km/hr`

Length of water flow in 30min.=`1/2` hour=`100xx1000/2`=50000` m

As we know that volume of water=`lxxbxxh`=`3xx1.2xx50000`

Depth of water in field=`8/100` m

`therefore` area of field=`(volume of water/depth of water)`

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