If `V` is the volume of a cuboid of dimensions `x ,\ y ,\ z\ a n d\ A` is its surface area, then `A/V` (a) `x^2y^2z^2` (b) `1/2(1/(x y)+1/(y z)+1/(z x))` (c) `2(1/x+1/y+1/z)` (d) `1/(x y z)`

Explanation

As we know that the dimensions of cuboid is x,y and z.

Now, S.A of cuboid is 2(xy+yz+zx)

Volume of cuboid = `xyz`

`therefore` `A/V`=`2((xy+yz+zx)/(xyz))`

`A/V=2(1/x+1/y+1/z)`