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The volume of a cube whose surface are...

The volume of a cube whose surface area is `96\ c m^2,` is (a) `16sqrt(2)\ c m^3` (b) `32\ c m^3` (c) `64\ c m^3` (d) `216\ c m^3`

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Verified by Experts

Given surface area = 96 cm^2
As we know that the surface area = `6a^2` ( a=side )
`96=6a^2`
`a^2=96/6`=`16`
`a=4 cm`
Now, volume of cube = `a^3`
`4^3`=`64cm^3`
Hence, Volume of a cube is `64cm^3`.
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