If each edge of a cuboid of surface area `S` is doubled, then surface area of the new cuboid is (a) 2 S (b) 4 S (c) 6 S (d) 8 S

Explanation

Let the length, breadth and height of cuboid are l, b and h.

Given: length, breadth and height of new cuboid are double of old cuboid.

So, let the length, breadth and height of new cuboid are L, B and H.

`therefore` `L=2l` , `B=2b` and `H=2h`

AS, we know that the surface area of cuboid(S) is `2(lbxxbhxxhl)

Surface area of new cuboid = `2(LBxxBHxxHL)`=`2(4lbxx4bhxx4hl)`=`4S`

Hence, option(b) is correct.