If the radius of the base of a right circular cylinder is halved, keeping the height same, what is the ratio of the volume of the reduce cylinder to that of the original.

Explanation

Radius of the cylinder = `r`

New radius of the base of a right circular cylinder = `r/2`

Original and new height of cylinder = `h`

Ratio of Volume of new cylinder to original cylinder =
`pi(r/2)^2h`/`pir^2h`

Required ratio = `1:4`