The inner diameter of a cylindrical wooden pipe is 24cm and its outer diameter is 28cm. The length of the pipe is 35cm. Find the mass of the pipe, if `1\ c m^3` of wood has a mass of 0.6 gm.

Explanation

Inner diameter, `d=24cm`

Inner radius, `r=24/2`=`12cm`

Outer diameter, `D=28cm`

Outer radius, `R=28/2`=`14cm`

Height, `h=35cm`

Volume of wood used = Outer volume - Inner volume

Volume of wood used = `piR^2h-pir^2h`

Volume of wood used = `22/7xx35(14^2-12^2)`

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