If the diameter of the base of a closed right circular cylinder be equal to its height `h ,` then its whole surface area is
(a) `2pih^2`
(b) `3/2pih^2`
(c) `4/3pih^2`
(d) `pih^2`

Explanation

Diameter=height of cylinder=`h`

radius = half of diameter=`h/2`

whole surface area= `2pir^2+2pirh`

=> Answer-`3/2 xx pih^2`