The radius and height of a cone are in the ratio 3:4. If its volume is `301. 44\ c m^3,` what is its radius? What is its slant height? `(T a k e\ pi=3. 14)`

Explanation

let radius and height of a cone are 3x,4x

given that volume `=301.44cm^3`

or, `(1/3)pi(r^2)h=301.44cm^3`

or,`x^3=8`

so `x=2`

so radius and height of a cone `=3xx2 ,4xx2`

`=6cm,8cm`

so slant height `l=(r^2+h^2)^(1/2)`

...