If the height and radius of a cone of volume `V` are doubled, then the volume of the cone, is (a) 3 V (b) 4 V (c) 6 V (d) 8 V

Explanation

As we know that the volume of a cone is `1/3pir^2h`

Here, `r=2r` and `h=2h`

Now, Volume of a cone = `1/3pi(2r)^2(2h)`

Volume of a cone(V) = `8(1/3pir^2h)`=`8V`

Hence, option(d) is correct.