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In millikon's method of determining the ...

In millikon's method of determining the charge of an electron, the terminal velocities of oil drop in the presence and in the absence of an electric field are `xcm//s` upward and `y cm//s` downwards respectively. Find the ratio of electric force to gravitational force on the oil drop . ( Neglect Buoyancy)

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In Gravitational field , weight = viscous force `w=6pieta ry……..(1)` in electric filed , Electric force = weight + viscous force `w_(q) =w + 6 pietarx ……….(2)` Substitute `(1)` in `(2)` then `E_(q) = 6 pietar(y+x)……….(3)`
`("Electric Force") / ("Gravitational force") =(x+y)/(y)`
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