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A charged oil drop fall with a terminal ...

A charged oil drop fall with a terminal velocity `V` in the absence of elcectric field . An electric field `E` keep keep the oil drop stationary in it . When the drop acquire a charge 'q' it moves up with same velocity. Find the initial charge on the drop.

Text Solution

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`mg = 6pietar upsilon,Eq=mg`
`E(Q+q)= mg +6pietar upsilon, E(Q+q)= 2 EQ`
` Q+q= 2 Q rArr q=Q`
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